Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 1 - Chemical Foundations - Exercises - Page 36: 55


$6.3*10^5 \text{kg}$

Work Step by Step

Volume of lake in mL = $$100 \text{ square miles}*20 \text{ feet}= 5.57568*10^{10} \text{ ft}^3*\frac{28316.8 \text{ mL}}{1 \text{ ft}^3}=1.578854*10^{15} \text{ mL}$$ $$1.578854*10^{15} \text{ mL}*\frac{0.4 \mu\text{g Hg}}{1 \text{ mL} }*\frac{1 \text{ kg Hg}}{10^9 \mu\text{g Hg}}=6.3*10^5 \text{kg}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.