Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 9 - Thermochemistry: Chemical Energy - Section Problems - Page 351: 58

Answer

-0.30 kJ

Work Step by Step

We find: $\Delta V=50.0\,mL-(50\,mL+50\,mL)=-50.0\,mL=-0.0500\,L$ $P\Delta V=1.5\,atm\times -0.0500\,L=-0.075\,L\,atm$ $=-0.075\,L\,atm\times\frac{101.325\,J}{1\,L\,atm}=-7.6\,J=-7.6\times10^{-3}\,kJ$ $\Delta E=\Delta H-P\Delta V$ $=-0.31\,kJ-(-7.6\times10^{-3}\,kJ)=-0.30\,kJ$
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