Answer
1400-kg car.
Work Step by Step
Kinetic energy $K.E=\frac{1}{2}mv^{2}$
For the car,
$K.E=\frac{1}{2}\times1400\times(115)^{2}=9.3\times10^{6}$
For the truck,
$K.E=\frac{1}{2}\times12000\times(38)^{2}=8.7\times10^{6}$
The car has more kinetic energy.
