Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 9 - Thermochemistry: Chemical Energy - Chapter Problems - Page 355: 137

Answer

279 K

Work Step by Step

We find: $\Delta S_{fus}=\frac{\Delta H_{fus}}{T_{m}}\implies T_{m}=\frac{\Delta H_{fus}}{\Delta S_{fus}}$ $=\frac{9.95\times10^{3}\,J/mol}{35.7 \,J/K\cdot mol }=279\,K$
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