Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 5 - Periodicity and the Electronic Structure of Atoms - Section Problems - Page 189: 36

Answer

$5.5×10^{-8}m$

Work Step by Step

Using the relation λ = $\frac{c}{ν}$, where λ is the wavelength, c is the speed, and ν is the frequency, we get : λ = $\frac{2.997925×10^{8}m/s}{5.5×10^{15}s^{-1}}$= $5.5\times10^{-8}m$
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