Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 4 - Reactions in Aqueous Solution - Chapter Problems - Page 152: 138



Work Step by Step

Equilibrium equation of the reaction is: $MgF_{2}\rightleftharpoons Mg^{2+}+2F^{-}$ Therefore, $K_{sp}=[Mg^{2+}][F^{-}]^{2}$ If S= solubility of $MgF_{2}$, then $[Mg^{2+}]=2.6\times10^{-4}\,mol/L=S$; $[F^{-}]=2S$ and $K_{sp}=(S)(2S)^{2}=4S^{3}=4(2.6\times10^{-4})=7.0\times10^{-11}$
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