Answer
(a) 159.70g/mol
(b) 98.09g/mol
(c) 192.12g/mol
(d) 334.39g/mol
Work Step by Step
(a)
Molar Mass ($Fe_2O_3$):
(Fe) 55.85* 2 + (O )16.00* 3 = 159.70g/mol
(b)
Molar Mass ($H_2SO_4$):
(H) 1.008* 2 + (S) 32.07* 1 + (O)16.00* 4 = 98.09g/mol
(c)
Molar Mass ($C_6H_8O_7$):
(C) 12.01* 6 + (H) 1.008* 8 + (O) 16* 7 = 192.12g/mol
(d)
Molar Mass ($C_{16}H_{18}N_2O_4S$):
(C) 12.01* 16 + (H) 1.008* 18 + (N) 14.01* 2 + (O) 16.00* 4 + (S)32.07* 1 = 334.39g/mol
