#### Answer

The percent atom economy is equal to $70.0\%$

#### Work Step by Step

1. Calculate the molecular weight of all the reactants.
Propanol:
** Count the amount of atoms of each type, and multiply them by the molecular weight of the element.
C: $(3)*(12.0) = 36.0$
O: $(1)*(16.0) = 16.0$
H: $(8)*(1.0) = 8.0$
$36.0 + 16.0 + 8.0 = 60.0$ $u$.
2. Calculate the molecular weight of the desired products (Propene):
C: $(3)*(12.0) = 36.0$
H: $(6)*(1.0) = 6.0$
$36.0 + 6.0 = 42.0$ $u$.
3. Use the formula to calculate the percent atom economy:
$\frac{42.0}{60.0} \times 100\% = 70.0\%$