## Chemistry (7th Edition)

The percent atom economy is equal to $70.0\%$
1. Calculate the molecular weight of all the reactants. Propanol: ** Count the amount of atoms of each type, and multiply them by the molecular weight of the element. C: $(3)*(12.0) = 36.0$ O: $(1)*(16.0) = 16.0$ H: $(8)*(1.0) = 8.0$ $36.0 + 16.0 + 8.0 = 60.0$ $u$. 2. Calculate the molecular weight of the desired products (Propene): C: $(3)*(12.0) = 36.0$ H: $(6)*(1.0) = 6.0$ $36.0 + 6.0 = 42.0$ $u$. 3. Use the formula to calculate the percent atom economy: $\frac{42.0}{60.0} \times 100\% = 70.0\%$