Chapter 2 - Atoms, Molecules, and Ions - Worked Example - Page 49: 6

$40$ $Earth-circumferences$

Using unit conversions, we find: $\frac{1.5 \times 10^{-10}m}{1-atom} \times 10^{19} atoms \times \frac{1km}{1000m} \times \frac{1-Earth-circumference}{40075 km} =$ $40$ $Earth-circumferences$