Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 2 - Atoms, Molecules, and Ions - Worked Example - Page 49: 6


$40$ $Earth-circumferences$

Work Step by Step

Using unit conversions, we find: $\frac{1.5 \times 10^{-10}m}{1-atom} \times 10^{19} atoms \times \frac{1km}{1000m} \times \frac{1-Earth-circumference}{40075 km} =$ $40$ $Earth-circumferences$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.