Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 2 - Atoms, Molecules, and Ions - Worked Example - Page 49: 6

Answer

$40$ $Earth-circumferences$

Work Step by Step

Using unit conversions, we find: $\frac{1.5 \times 10^{-10}m}{1-atom} \times 10^{19} atoms \times \frac{1km}{1000m} \times \frac{1-Earth-circumference}{40075 km} =$ $40$ $Earth-circumferences$
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