Answer
64.2 h
Work Step by Step
Half-life $t_{1/2}=\frac{0.693}{k}$ where $k$ is the decay constant.
$\implies t_{1/2}=\frac{0.693}{1.08\times10^{-2}\,h^{-1}}=64.2\,h$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 19 - Nuclear Chemistry - Worked Example - Page 817: 5
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