Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 17 - Thermodynamics: Entropy, Free Energy and Equilibrium - Section Problems - Page 750: 53

Answer

$1.27\times10^{-20}\,J/K$

Work Step by Step

Number of ways $W=B^{N}=10000^{100}=(10^{4})^{100}=10^{400}$ $S=k\ln W$ where the Boltzmann constant $k=1.38\times10^{-23}\,J/K$ Then $S=(1.38\times10^{-23}\,J/K)\times \ln (10^{400})$ $=1.27\times10^{-20}\,J/K$
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