Answer
$78^{\circ}C$
Work Step by Step
We find:
$T_{b}=\frac{\Delta H_{vap}}{\Delta S_{vap}}=\frac{38.6\,kJ/mol}{0.110\,kJmol^{-1}K^{-1}}=351\,K$
$=351-273= 78^{\circ} C$
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