Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 16 - Applications of Aqueous Equilibria - Section Problems - Page 710: 77

Answer

The blood pH for this blood is equal to 7.10.

Work Step by Step

1. Calculate the pKa value for carbonic acid: $pKa = -log(Ka)$ $pKa = -log( 7.9 \times 10^{- 7})$ $pKa = 6.10$ 2. Use the Henderson-Hasselbalch equation: $pH = pKa + log(\frac{[Base]}{[Acid]})$ $pH = 6.10 + log(10)$ $pH = 6.10 + 1.00 = 7.10$
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