Answer
(a) $pH = 8.199$
(b) $pH = 4.222$
Work Step by Step
(a)
$pOH = -log[OH^-]$
$pOH = -log( 1.58 \times 10^{- 6})$
$pOH = 5.801$
$pH + pOH = 14$
$pH + 5.801 = 14$
$pH = 8.199$
(b)
$pH = -log[H_3O^+]$
$pH = -log( 6 \times 10^{- 5})$
$pH = 4.222$
