# Chapter 15 - Aqueous Equilibria: Acids and Bases - Worked Example - Page 615: 9

$[OH^-] = 7.143 \times 10^{- 11}M$ The solution is acidic.

#### Work Step by Step

$[H_3O^+] * [OH^-] = Kw = 10^{-14}$ $1.4 \times 10^{- 4} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 1.4 \times 10^{- 4}}$ $[OH^-] = 7.143 \times 10^{- 11}M$ Since: $[H_3O^+] > [OH^-]$, the solution is acidic.

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