## Chemistry (7th Edition)

$[OH^-] = 7.143 \times 10^{- 11}M$ The solution is acidic.
$[H_3O^+] * [OH^-] = Kw = 10^{-14}$ $1.4 \times 10^{- 4} * [OH^-] = 10^{-14}$ $[OH^-] = \frac{10^{-14}}{ 1.4 \times 10^{- 4}}$ $[OH^-] = 7.143 \times 10^{- 11}M$ Since: $[H_3O^+] > [OH^-]$, the solution is acidic.