Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 15 - Aqueous Equilibria: Acids and Bases - Worked Example - Page 613: 7


(a) $H_2Se$ (b) $HI$ (c) $HNO_3$ (d) $H_2SO_3$

Work Step by Step

(a) $S$ and $Se$ are on the same group of the periodic table, therefore, the important factor is the bond strength. Since $Se$ is a bigger atom, the bond will be weaker, and its acid will be stronger. (b) $I$ and $Te$ are on the same row, therefore, the polarity is the important factor. And since $I$ is more electronegative than $Te$, the polarity is greater, and the bond $H - I$ is weaker. (c) The factor here will be the Oxydation number of the central atom: "N": For $HNO_2$, this number is +3, and for $HNO_3$, this number is +5. Therefore, $HNO_3$ is a stronger acid. (d) The factor here will be the electronegativity of the central atom: Since $S$ is more electronegative than $Se$, $H_2SO_3$ is a stronger acid.
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