Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 15 - Aqueous Equilibria: Acids and Bases - Worked Example - Page 607: 3


First reactant: $HCl$: Acid. Second reactant: $NH_3$: Base. First product: $N{H_4}^+$: Acid. Second product: $Cl^-$: Base. Conjugate acid-base pairs: - $HCl$ and $Cl^-$ - $NH_3$ and $N{H_4}^+$

Work Step by Step

1. Identify the acids. - They are the species that are donating one $H^+$ in the reaction. For example: $HCl$ is turning into $Cl^-$ during the reaction, therefore, it is donating one proton: $HCl = Acid$ 2. Identify the bases. - They are the species that are receiving one $H^+$ in the reaction: For example: $Cl^-$ is turning into $HCl$ during the reverse reaction, therefore, it is receiving one $H^+$: $Cl^- = Base$ 3. To identify a conjugate acid-base pair, you just have to find the two species that just differ by one ($H^+$), for example: $N{H_4}^+$ and $NH_3$.
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