Answer
First reactant: $HCl$: Acid.
Second reactant: $NH_3$: Base.
First product: $N{H_4}^+$: Acid.
Second product: $Cl^-$: Base.
Conjugate acid-base pairs:
- $HCl$ and $Cl^-$
- $NH_3$ and $N{H_4}^+$
Work Step by Step
1. Identify the acids.
- They are the species that are donating one $H^+$ in the reaction.
For example: $HCl$ is turning into $Cl^-$ during the reaction, therefore, it is donating one proton: $HCl = Acid$
2. Identify the bases.
- They are the species that are receiving one $H^+$ in the reaction:
For example: $Cl^-$ is turning into $HCl$ during the reverse reaction, therefore, it is receiving one $H^+$: $Cl^- = Base$
3. To identify a conjugate acid-base pair, you just have to find the two species that just differ by one ($H^+$), for example:
$N{H_4}^+$ and $NH_3$.
