## Chemistry (7th Edition)

$[H_3O^+] = 5 \times 10^{- 9}M$ It is a basic solution.
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$ $2 \times 10^{- 6} * [H_3O^+] = 10^{-14}$ $[H_3O^+] = \frac{10^{-14}}{ 2 \times 10^{- 6}}$ $[H_3O^+] = 5 \times 10^{- 9}$ - Since $[OH^-] > [H_3O^+]$, the solution is basic.