Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 15 - Aqueous Equilibria: Acids and Bases - Section Problems - Page 649: 64

Answer

$[H_3O^+] = 5 \times 10^{- 9}M$ It is a basic solution.

Work Step by Step

$[OH^-] * [H_3O^+] = Kw = 10^{-14}$ $ 2 \times 10^{- 6} * [H_3O^+] = 10^{-14}$ $[H_3O^+] = \frac{10^{-14}}{ 2 \times 10^{- 6}}$ $[H_3O^+] = 5 \times 10^{- 9}$ - Since $[OH^-] > [H_3O^+]$, the solution is basic.
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