Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 14 - Chemical Equilibrium - Section Problems - Page 595: 66

Answer

$$K_c = 5.8 \times 10^{-2}$$

Work Step by Step

1. Write the equilibrium constant expression: - The exponent of each concentration is equal to its balance coefficient. $$K_c = \frac{[Products]}{[Reactants]} = \frac{[ PCl_3 ][ Cl_2 ]}{[ PCl_5 ]}$$ 2. Substitute the values and calculate the constant value: $$K_c = \frac{( 1.5 x 10^{-2} )( 3.2 x 10^{-2} )}{( 8.3 x 10^{-3} )} = 5.8 \times 10^{-2}$$
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