## Chemistry (7th Edition)

Published by Pearson

# Chapter 14 - Chemical Equilibrium - Section Problems - Page 594: 54

#### Answer

$K_c = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$ (b) $K_c = \frac{[ClF_3]^2}{[F_2]^3[Cl_2]}$ (c) $K_c = \frac{[HF]^2}{[H_2][F_2]}$

#### Work Step by Step

(a) The balancing coefficient of the hydrogen gas $(H_2(g))$ is "3", so that will be the exponent of its concentration. $K_c = \frac{[Products]}{[Reactants]} = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$ The balancing coefficient of the $F_2(g)$ is "3", so that will be the exponent of its concentration. The balancing coefficient of the $ClF_3(g)$ is "2", so that will be the exponent of its concentration. (b) $K_c = \frac{[Products]}{[Reactants]} = \frac{[ClF_3]^2}{[F_2]^3[Cl_2]}$ The balancing coefficient of the $HF(g)$ is "2", so that will be the exponent of its concentration. (c) $K_c = \frac{[Products]}{[Reactants]} = \frac{[HF]^2}{[H_2][F_2]}$

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