## Chemistry (7th Edition)

Published by Pearson

# Chapter 13 - Chemical Kinetics - Section Problems - Page 546: 78

#### Answer

$2.79\times10^{-3} s^{-1}$

#### Work Step by Step

Recall that $t_{1/2}=\frac{0.693}{k}$ or $k=\frac{0.693}{t_{1/2}}$. That is, $k=\frac{0.693}{248 s}=2.79\times10^{-3}s^{-1}$

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