Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 13 - Chemical Kinetics - Section Problems - Page 546: 78


$2.79\times10^{-3} s^{-1}$

Work Step by Step

Recall that $t_{1/2}=\frac{0.693}{k}$ or $k=\frac{0.693}{t_{1/2}}$. That is, $k=\frac{0.693}{248 s}=2.79\times10^{-3}s^{-1}$
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