Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 12 - Solutions and Their Properties - Section Problems - Page 488: 120


0.197 M

Work Step by Step

Given: $\Pi= 4.85\,atm$ T= 300 K and we know that $R= 0.0821 L\,atm\,mol^{-1}K^{-1}$ Recall: $\Pi= cRT$ or $c=\frac{\Pi}{RT}$ Substituting the values: $c= \frac{4.85\,atm}{0.0821\,L\,atmK^{-1}mol^{-1}\times300K}$ Result: Molarity c= 0.197 M
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