## Chemistry (7th Edition)

I would use $6.32$ $mL$ of this substance.
Use the given mass and density to calculate the necessary volume: $9.37$ $g$ $\times \frac{1mL}{1.483 g} = 6.32$ $mL$ Or you can use the expression: $density = \frac{mass}{Volume}$ $Volume = \frac{mass}{density} = \frac{9.37g}{1.483g/mL} = 6.32$ $mL$