Answer
I would use $6.32$ $mL$ of this substance.
Work Step by Step
Use the given mass and density to calculate the necessary volume:
$9.37$ $g$ $\times \frac{1mL}{1.483 g} = 6.32$ $mL$
Or you can use the expression:
$density = \frac{mass}{Volume}$
$Volume = \frac{mass}{density} = \frac{9.37g}{1.483g/mL} = 6.32$ $mL$
