Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 1 - Chemical Tools: Experimentation and Measurement - Worked Example - Page 14: 5


I would use $6.32$ $mL$ of this substance.

Work Step by Step

Use the given mass and density to calculate the necessary volume: $9.37$ $g$ $\times \frac{1mL}{1.483 g} = 6.32$ $mL$ Or you can use the expression: $density = \frac{mass}{Volume}$ $Volume = \frac{mass}{density} = \frac{9.37g}{1.483g/mL} = 6.32$ $mL$
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