Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 1 - Chemical Tools: Experimentation and Measurement - Section Problems - Page 30: 58


(a) $4.5332 \times 10^2$ $mg$ (b) $4.21 \times 10^{-5}$ $mL$ (c) $6.67 \times 10^5$ $g$

Work Step by Step

1. Move the decimal point to get the number between 1 and 10. (a) $4.5332 $ $mg$ (b) $4.21 $ $mL$ (c) $6.67$ $g$ 2. Now, multiply the number by 10 to the power of the number of times you moved the decimal point. If you moved to the right, the number is negative. (a) We moved the decimal point by 2 times to the left: $4.5332 \times 10^2$ $mg$ (b) We moved the decimal point by 5 times to the right: (b) $4.21 \times 10^{-5}$ $mL$ (c) We moved the decimal point by 5 times to the left: (c) $6.67 \times 10^5$ $g$
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