Chapter 1 - Chemical Tools: Experimentation and Measurement - Chapter Problems - Page 31: 101

$8.9\times10^{10}\,L$

We find: $1\,lb= 453.592\, g$ $\implies 3.6\times10^{11}\,lb=3.6\times10^{11}\,lb\times\frac{453.592\,g}{1\,lb}$ $=1.63293\times10^{14}\,g$ $\text{Volume}=\frac{\text{mass}}{\text{density}}=\frac{1.63293\times10^{14}\,g}{1.8302\,g/cm^{3} }=8.9\times10^{13}\,cm^{3}$ $=8.9\times10^{13}\,cm^{3}\times\frac{1\,L}{1000\,cm^{3}}$ $=8.9\times10^{10}\,L$