Answer
$$\therefore \text{no. of orbitals }=5$$
Work Step by Step
$\textbf{Note: } $ The number of orbitals in a subshell ( $l$ ) is equal to $2l + 1$.
Therefore, the number of orbitals in the subshell $l=2$
$$\text{no. of orbitals }=2\times 2+1=5$$
