Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 6 - Section 6.4 - Wave Properties of Matter - Checkpoint - Page 253: 6.4.2

Answer

$$\therefore p = 5.43\times 10^{-27}\text{ kg.m/s}$$

Work Step by Step

The momentum of a photon is given by the equation: $$p = \frac{h}{\lambda}$$ Given $\lambda = 122\text{ nm }=122\times 10^{-9}\text{ m}$ $$\therefore p = \frac{6.67\times 10^{-34}}{122\times 10^{-9}} = 5.43\times 10^{-27}\text{ kg.m/s}$$
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