Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 6 - Section 6.1 - The Nature of Light - Checkpoint - Page 237: 6.1.3

Answer

(b) $2.00\times10^{8}\,m/s$

Work Step by Step

Speed $v=\lambda \nu$ where $\lambda$ is the wavelength and $\nu$ is the frequency. That is, $v=684\times10^{-9}m\times 2.92\times10^{14}\,s^{-1}$ $=2.00\times10^{8}\,m/s$
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