## Chemistry (4th Edition)

As the reaction gives off heat, $q_{rxn}$ is negative. Heat capacity of the calorimeter $C_{cal}= \frac{q_{cal}}{\Delta T}=\frac{-q_{rxn}}{\Delta T}=\frac{-(-26.42\,kJ)}{(27.20-23.40)^{\circ}C}$ $=6.95\,kJ/^{\circ}C$