Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 5 - Section 5.3 - Enthalpy - Checkpoint: 5.3.1

Answer

b) 453 kJ.

Work Step by Step

Converting mass in grams to the mole; 1 kg $Br_{2} \times\frac{1 mole Br_{2}}{159.808g}$ = 6.2575 mol. We multiply the whole reaction by 6.2575 mol. Then, $\Delta H = 6.2575mol\times-72.4 kJ/mol.$ = -453 kJ. 453 kJ heat is evolved.
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