Answer
b) 453 kJ.
Work Step by Step
Converting mass in grams to the mole;
1 kg $Br_{2} \times\frac{1 mole Br_{2}}{159.808g}$ = 6.2575 mol.
We multiply the whole reaction by 6.2575 mol.
Then, $\Delta H = 6.2575mol\times-72.4 kJ/mol.$ = -453 kJ.
453 kJ heat is evolved.
