Answer
c) w= $-5.4\times10^{2}$ kJ, done by the system.
Work Step by Step
q = -928 kJ. (Heat is released, so q is negative.)
$\Delta U = -1.47\times10^{3} kJ.$
$\Delta U$ = q+w, Or w=$\Delta U-q = -1.47\times10^{2} kJ -(-928 kJ)$ = $-5.4\times10^{2}$ kJ. Negative sign indicates that the work is done by the system.
