Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 5 - Questions and Problems - Page 230: 5.145



Work Step by Step

Specific heat $s=\frac{C}{m}$ where $C$ is the heat capacity and $m$ is the mass. Then, $s=\frac{85.7\,J/^{\circ}C}{362\,g}=0.237\,J/g\cdot\,^{\circ}C$
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