Answer
3.31 kJ
Work Step by Step
Specific heat of copper metal
$s=0.139\,J/g\cdot \,^{\circ}C$
Mass $m= 366\,g$
Change in temperature
$\Delta T= (12.0-77.0)^{\circ}C=-65.0^{\circ}C$
Heat transferred $q=sm\Delta T$
$=0.139\,J/g\cdot \,^{\circ}C\times366\,g\times-65.0^{\circ}C$
$=-3310\,J=-3.31\,kJ$
Negative sign indicates that the heat is liberated.
3.31 kJ heat is liberated.
