Answer
a) 225 g
Work Step by Step
1L solution contains of 2.5 mol
0.5 L solution contains of x mol
x=n=1.25 mol
n (mol) = mass (g)/ Mw (g/mol) , where Mw is the molecular weight of glucose and equal to 180 g/mol
→ mass (g) = 1.25*180 = 225 g
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 4 - Section 4.5 - Concentration of Solutions - Checkpoint - Page 164: 4.5.2
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