Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 3 - Section 3.4 - The Mole and Molar Masses - Checkpoint - Page 99: 3.4.2


d) 1.14 mol.

Work Step by Step

Molar mass = 14.007g+(3$\times$1.008g)= 17.031g 1 mole of Ammonia contains 3 moles of hydrogen. i.e, 17.031g contains 3 mol hydrogen. Or 1 g contains $\frac{3}{17.031}$ mol. Then, 6.50g contains ($\frac{3}{17.031}\times 6.50) $mol= 1.14 mol.
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