Answer
The correct answer is:
d) 498.44 amu
Work Step by Step
($Ca_3(C_6H_5O_7)_2$):
Given:
$Ca = 40.08$ $amu$
$C = 12.01$ $amu$
$H = 1.008$ $amu$
$O = 16.00$ $amu$
40.08* 3 + 2 * ( 12.01* 6 + 1.008* 5 + 16* 7 ) = 498.44g/mol
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 3 - Section 3.1 - Molecular and Formula Masses - Checkpoint - Page 85: 3.1.2
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