Answer
C:$$ 88.16 \% $$
H:$$11.84 \% $$
Work Step by Step
1. Count the amount of black spheres (Carbons) and white spheres (Hydrogens).
$$C_{10}H_{16}$$
2. Calculate the percent composition by mass.
$ C_{10}H_{16} $ : ( 1.008 $\times$ 16 )+ ( 12.01 $\times$ 10 )= 136.23 g/mol
C:$$\frac{( 12.01 \times 10 )}{136.23 } \times 100\% = 88.16 \% $$
H:$$\frac{( 1.008 \times 16 )}{136.23 } \times 100\% = 11.84 \% $$
