Answer
a) $2.6\times10^{-10}\,s^{-1}$
Work Step by Step
Half-life $t_{1/2}=86\,years$
Rate constant $k=\frac{0.693}{t_{1/2}}=\frac{0.693}{86\,y}=\frac{0.693}{86\times3600\times24\times365\,s}$
$=2.6\times10^{-10}\,s^{-1}$
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 20 - Standardized-Exam Practice Problems - Page 955: 1
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