Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 20 - Standardized-Exam Practice Problems - Page 955: 1


a) $2.6\times10^{-10}\,s^{-1}$

Work Step by Step

Half-life $t_{1/2}=86\,years$ Rate constant $k=\frac{0.693}{t_{1/2}}=\frac{0.693}{86\,y}=\frac{0.693}{86\times3600\times24\times365\,s}$ $=2.6\times10^{-10}\,s^{-1}$
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