Answer
e) 5:4
Work Step by Step
so we have to calculate the ratio:-
$\frac{g\space yellow : 1.00 g\space blue (right)}{g \space yellow : 1.00 g\space blue (left)}$
now given are 2 different compounds
one has 1 blue and 2 yellow
another one has 2 blue and 5 yellow
now let us calculate
$\frac{g\space yellow : 1.00 g\space blue (right)}{g\space yellow : 1.00 g\space blue (left)}$
=$\frac{5 g \space yellow : 2.00 g\space blue (right)}{2g\space yellow : 1.00 g\space blue (left)}$
= $\frac{5 g \space yellow : 2.00 g\space blue (right)}{4g\space yellow : 2.00 g\space blue (left)}$
i.e doubled denominator
=$\frac{5 g \space yellow : 1.00 g\space blue (right)}{4g\space yellow : 1.00 g\space blue (left)}$
division $2\div2$ equals 1
$\frac{g\space yellow : 1.00 g\space blue (right)}{g \space yellow : 1.00 g\space blue (left)}$ = $\frac{5}{4}$
so, the final answer is e) 5:4
