## Chemistry (4th Edition)

(a) $NaOH$ is a strong base, and $HBr$ is a strong acid; therefore, this salt is nearly neutral, because both conjugate pairs will not affect the pH. (b) $KOH$ is a strong base, and $HSO_3^-$ is a weak acid; therefore, this salt is basic. (c) $NH_3$ is a weak base, and $HNO_2$ is a weak acid. But, if we compare their equilibrium constant for ionization, $HNO_2$ is stronger; therefore, $NH_4NO_2$ is acidic. (d) $Cr(OH)_3$ is a weak base, and $HNO_3$ is a strong acid; therefore, this salt will create an acidic solution.