## Chemistry (4th Edition)

d) $$K_{sp} = 3.4 \times 10^{-6}$$
For the reaction: $$A_2X(s) \leftrightharpoons 2A^+(aq)+X^{2-}(aq)$$ 1. Write the equilibrium constant expression: - The exponent of each concentration is equal to its balance coefficient. $$K_c = \frac{[Products]}{[Reactants]} = \frac{[ A^+ ]^{ 2 }[ X^{2-} ]}{1}$$ 2. At equilibrium, these are the concentrations of each compound: $[ A^+ ] = 2x$ $[ X^{2-} ] = x$ $0.019 = 2x \longrightarrow x = 0.0095$ $[X^{2-}] = 0.0095$ $$K_{sp} = (0.019)^2(0.0095) = 3.4 \times 10^{-6}$$