Answer
d) 8.908 g/cm3 is right answer
Work Step by Step
Given :
The FCC of nickel has an edge length = 352.4 pm =$352.4 \times 10^{-10}$ cm
The atomic mass of nickel is = 58.7 u
so we have to find the density of nickel
we know , In FCC there are 4 atoms present
Density = $\frac{no\space of \space atoms \times mass \space of\space atom}{edge\space length^{3}\times Avogadro's number}$
Density =$\frac{4 \times 58.7}{(352.4 \times 10^{-10})^{3} \times 6.022 \times 10^{23}}$ = $\frac{234.8}{26.3522}$ = 8.90834 g $cm^{-3}\approx$ 8.9 g/cm3
So, the correct answer is d) 8.908 g/cm3
