Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Section 10.2 - The Gas Laws - Checkpoint - Page 437: 10.2.4

Answer

The correct answer is (a) 120 mL

Work Step by Step

1. Find the excess/limiting reactants $\frac{180 mL}{3} = 60 mL$ $\frac{60 mL}{1 } = 60 mL$ They have stoichiometric equivalence, so it does not matter which one we use to find the amount of product. 2. $$\frac{180 mL \ H_2}{3} \times {2} = 120 \ mL \ NH_3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.