Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Section 10.2 - The Gas Laws - Checkpoint - Page 436: 10.2.2


a) 100 mL

Work Step by Step

According to Charles' law, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ Then, $V_{2} = \frac{V_{1}T_{2}}{T_{1}} = \frac{50.0mL\times(316+273.15)K}{(21.5+273.15)K}$ = 100. mL
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