Answer
$49.7Kg$
Work Step by Step
The mass of the bronze cylinder can be determined as follows:
First of all, we will find the volume of the bronze
$V=\pi r^2 h$
$\implies V=3.1416(6.44)^2(44.37)=5781.1cm^3$
The total density can be determined
$Total \space density=0.7942g\space Cu (8.94g/cm^3)+0.2058g\space Cu(7.31g/cm^3)=8.60g/cm^3$
Now, mass of the bronze cylinder is calculated as
$m=density\times volume$
We plug in the known values to obtain:
$m=8.60\times 5781.1=49717.46g=49.7Kg$
While solving this problem, we should make the assumption that the bronze cylinder is at room temperature to keep the density constant.
