## Chemistry (4th Edition)

a) $-196^{\circ}C$ b) $-268.93^{\circ}C$ c) $327.46^{\circ}C$
Use the relation $t = T-273.15$, where T is the temperature in Kelvin and t is the temperature in Celsius. a) t = $(77-273.15)^{\circ}C = -196^{\circ}C$ b) t = $(4.22-273.15)^{\circ}C = -268.93^{\circ}C$ c) t = $(600.61-273.15)^{\circ}C = 327.46^{\circ}C$