Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 1 - Questions and Problems - Page 31: 1.30


a) $-196^{\circ}C$ b) $-268.93^{\circ}C$ c) $327.46^{\circ}C$

Work Step by Step

Use the relation $t = T-273.15$, where T is the temperature in Kelvin and t is the temperature in Celsius. a) t = $(77-273.15)^{\circ}C = -196^{\circ}C$ b) t = $(4.22-273.15)^{\circ}C = -268.93^{\circ}C$ c) t = $(600.61-273.15)^{\circ}C = 327.46^{\circ}C$
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