Answer
Please see the answer below.
Work Step by Step
(a) Li - $1s^{2}2s^{1}$
Lithium contains one electron in its valence shell. By losing one electron in the valence shell $Li^{+}$ is formed.
(b) Cl - $1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}$
Chlorine contains seven electrons in its valence shell. By accepting one electron $Cl^{-}$ is formed.
(c) S - $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$
Sulfur contains six electrons in its valence shell. By accepting two electrons $S^{2-}$ is formed.
(d) Sr - $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}$
Strontium contains two electrons in its valence shell. By losing two electrons in the valence shell $Sr^{2+}$ is formed.
(e) N - $1s^{2}2s^{2}2p^{3}$
Nitrogen contains five electrons in its valence shell. By accepting three electrons $N^{3-}$ is formed.
