Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 8 - Periodic Relationships Among the Elements - Questions & Problems - Page 363: 8.93

Answer

Please see the work below.

Work Step by Step

$P_{4}O_{10} + 6 H_{2}O → 4 H_{3}PO_{4}$ Diphosphorus pentoxide reacts with water to form Phosphoric acid. $N_{2}O_{5} + H_{2}O → 2 HNO_{3}$ Nitrogen pentoxide reacts with water to form Nitric acid. $Na_{2}O + H_{2}O → 2 NaOH$ Sodium oxide reacts with water to form Sodium hydroxide $BaO + H_{2}O → Ba(OH)_{2} $ Barium oxide reacts with water to form Barium hydroxide $SO_{3} + H_{2}O → H_{2}SO_{4} $ Sulfur trioxide reacts with water to form Sulfuric acid.
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