Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems: 6.123

Answer

Please see the work below.

Work Step by Step

We know that for aluminium $c=0.9\frac{J}{C^{\circ}}$ and $m=26.98g$ $\implies mc=26.98\times 0.9=24.3\frac{J}{C^{\circ}}$
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