Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems - Page 268: 6.121


Please see the work below.

Work Step by Step

We can find the required energy as $K.E=0.17\times 500\times 3000=2.6\times 10^5J$ To find the height, we know that in the given scenario $K.E=P.E$ $2.6\times 10^5=mgh$ This simplifies to : $h=9.8\times 10^2m$
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